[OpenSIPS-Users] regex extract value from $ru

[Satish Patel]

Great!!! Thanks a lot

Sent from my iPhone

On Sep 14, 2014, at 4:41 AM, Liviu Chircu <liviu at opensips.org> wrote:

> Hello Satish,
> 
> There is no need for regex substitution, since OpenSIPS has lots       of useful variables. [1]
> 
> In your case, you could do:
> 
> $var(id) = "sip:" + $rd + ":" + $rp;
> 
> [1]: http://www.opensips.org/Documentation/Script-CoreVar-1-12
> 
> Best regards,
> Liviu Chircu
> OpenSIPS Developer
> http://www.opensips-solutions.com
> On 12.09.2014 23:48, Satish Patel wrote:
>> Following is $ru and i want to extract following  sip:sipprovider.com:5060
>> 
>> sip:123456789 at sipprovider.com:5060
>> 
>> to 
>> 
>> sip:sipprovider.com:5060
>> 
>> I am using following regex but its not working, does following make sense? 
>> 
>>  $var(z) = $ru;
>>         $var(z) = "s/[^:@]*@//";
>>         xlog("My regex $ru\n");
>> 
>> 
>> 
>> 
>> 
>> 
>> 
>> 
>> 
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> 
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