[OpenSIPS-Users] regex extract value from $ru

[Liviu Chircu]

Hello Satish,

There is no need for regex substitution, since OpenSIPS has lots of 
useful variables. [1]

In your case, you could do:

$var(id) = "sip:" + $rd + ":" + $rp;

[1]: http://www.opensips.org/Documentation/Script-CoreVar-1-12

Best regards,

Liviu Chircu
OpenSIPS Developer
http://www.opensips-solutions.com

On 12.09.2014 23:48, Satish Patel wrote:
> Following is $ru and i want to extract following  
> sip:sipprovider.com:5060 <http://sipprovider.com:5060>
>
> sip:123456789 at sipprovider.com:5060 
> <http://sip:123456789@sipprovider.com:5060>
>
> to
>
> sip:sipprovider.com:5060 <http://sipprovider.com:5060>
>
> I am using following regex but its not working, does following make 
> sense?
>
>  $var(z) = $ru;
>         $var(z) = "s/[^:@]*@//";
>         xlog("My regex $ru\n");
>
>
>
>
>
>
>
>
>
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