[Users] Is there a way to leave a route block and return to it where you left?

[Bogdan-Andrei Iancu]

Hi Brandon,

if you do "return" in route(101), the execution will continue in 
route(2) immediately after the route(101) call...Isn't that what you want?

regards,
bogdan

Brandon Price wrote:

> I have a route block that performs callerid name lookups for incoming 
> calls. I want to leave this as a separate route block, and not include 
> it into the incoming route for simplicity of development. I basically 
> want to hop out of route 2 down to route 101, then hop back to route 2 
> under the line that is pointed to. Any clues,? can this even be done 
> or does the structure of the tm (being stateless) limit it? Is there a 
> way to hop to a certain line number of a route like say route(2,4); 
> going to route 2 line 4. I dunno. 
>
>
> ###############################################################
> # INCOMING                                     
> ###############################################################
> route[2]                                               
> {                                                      
>         xlog("INVITE Received (incoming): $fu -> $ru");
>         setflag(1);                                    
>         strip(1);                                      
>         *route(101); <---*
> do more stuff .........................................         
>
> ##########################################################################################################
> # CNAM
> #########################################################################################################
> route[101]
> {
>        xlog("Running cnam query");
> #    do some stuff....
>        return;
> };     
>
>------------------------------------------------------------------------
>
>_______________________________________________
>Users mailing list
>Users at openser.org
>http://openser.org/cgi-bin/mailman/listinfo/users
>  
>